-16x^2+10x+114=0

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Solution for -16x^2+10x+114=0 equation:



-16x^2+10x+114=0
a = -16; b = 10; c = +114;
Δ = b2-4ac
Δ = 102-4·(-16)·114
Δ = 7396
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7396}=86$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-86}{2*-16}=\frac{-96}{-32} =+3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+86}{2*-16}=\frac{76}{-32} =-2+3/8 $

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